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Bash: Choose a random value out of a set


The best scripts are the shortest.
This chooses one of the arguments randomly. $# is the number of arguments

#!/bin/bash
echo ${BASH_ARGV[ $(( $RANDOM % $# )) ]}

Example:

$ bash randomchooser.sh 1 2 3 4 5 6 7 8 9 120
3

This entry was posted on Friday, November 28th, 2008 and is filed under Happy Hacking. You can follow any responses to this entry through RSS 2.0. You can leave a response, or trackback from your own site.

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